8 gauge choke dimensions

[Cold Spring]

Typical 10 and 8-gauge choke constrictions may be easily calculated using high school math and a "direct proportion" by using the surface area of a nominal 12-gauge .729" bore (Pi x R^2) and 12 gauge choke constrictions, and proportioning by using your measured 10 or 8-gauge bore diameter/surface area. Use 10-20-30 and 40 thou for 12-gauge IC-Mod-Imp Mod and X-Full). I could do that for you by hand or with an excel formula but as my sophomore high school professor Mr O'Hara used to say, that's your homework assignment.

Hey Mike, "a friend" suggested you give me a free round if I do that for you.

[Mike Franzen]

Originally Posted by Frank Srebro

Typical 10 and 8-gauge choke constrictions may be easily calculated using high school math and a "direct proportion" by using the surface area of a nominal 12-gauge .729" bore (Pi x R^2) and 12 gauge choke constrictions, and proportioning by using your measured 10 or 8-gauge bore diameter/surface area.

What Frank said …. I agree ….. 100% …..

[Mike of the Mountain]

By using direct proportions to convert 12g (using a .729 bore) to 8g bore/chokes, it works out to-
IC .010 = .012, M .020 = .023, IM .030 = .035 and F .040 = .046.

My bores are R .846 and L .847. R choke is .828 (.018) or LM. L choke is .831 (.016) which should also be LM.

I know someone will double check this and definitely tell me if I'm wrong.

Using the 3.14 x radius squared I still come up with LM-M choking.