I spoke with Dale for about an hour and a half's worth of great advice. I do have a math problem for the forum. I am mixing 3.5 liter solution of 10% Ferric Chloride. The ferric Chloride is a 38.4% concentration. The following are my naught naughts:
38.4% X = 10% 3.5 Liters
X = 10% 3.5 L divided by 38.4% (10% 3500 ml = 350)
X = 350/.384
X = 911.458 Milliliters
Almost 1/3 of my 10% ferric chloride solution will be ferric chloride. Its been a long time since I've had to do more the add and subtract. Please let me know if I'm on the right tack or off on a tangent.
Kindest, Harry
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