Lightening Grooves

[Bill Murphy]

Rich, most of us haven't seen a hammerless 20 with lightening cuts. Can you post a picture?

[C.O.B.]

Originally Posted by Dean Romig

Okay fellas, get out your slide-rules and figure the ounces saved on the lifter and the ounces saved on the T/A....... Ready - Get set - GO!!

Thats just to much math, whats a slide rule?

Bill its a 16

[Autumn Daze]

You guy's have way too much time on your hands.

[Dean Romig]

It's either this or go back to work...

[Double Play]

Originally Posted by Dean Romig

The lightening cuts on the 0-Frame lifter consist of one cut per side with a length of 1.92" each and a width of .38" wide each and a depth of .112" for the cut on the left water table and .102" for the cut on the right water table.

As a comparison, the lightening cuts on an 0-Frame T/A consisting of two cuts per flat are 1.37" in length each for the cuts to the rear of the check hook rod and .89" for the forward cuts. The width of these cuts are .37" wide and .102" deep.

Okay fellas, get out your slide-rules and figure the ounces saved on the lifter and the ounces saved on the T/A....... Ready - Get set - GO!!

I can't help you unless you give me the radius at the bottom of the slots.

[Bindlestiff]

Fill them with hot wax. After it cools, form it into a cube and measure it. No slide rule involved.

[Dean Romig]

Originally Posted by Larry Frey

I can't help you unless you give me the radius at the bottom of the slots.

Take the width of the slots and divide by 2 and you'll get the radius.

Actually, the depth is the radius in this case.

Remember though, the slots are perfectly rounded at each end so you'll need to multiply by pi in order to arrive at cu. in.

This is gettin' to be fun!

[Double Play]

Originally Posted by Dean Romig

The lightening cuts on the 0-Frame lifter consist of one cut per side with a length of 1.92" each and a width of .38" wide each and a depth of .112" for the cut on the left water table and .102" for the cut on the right water table.

Originally Posted by Dean Romig

Take the width of the slots and divide by 2 and you'll get the radius.

Actually, the depth is the radius in this case.

Remember though, the slots are perfectly rounded at each end so you'll need to multiply by pi in order to arrive at cu. in.

This is gettin' to be fun!

Not so grasshopper!

In your previous example you say half the width would equal the radius which would be correct if the depth also equaled at least half the width. But you are correct in that the radius at the ends must be taken into consideration.

[Bill Murphy]

Rich, we haven't seen a hammerless 16 with lightening cuts. Can we see a picture?

[10 bore]

Originally Posted by Dave Suponski

You guy's have way too much time on your hands.

have Pete lester do it, that will give him a break from looking for powder